Question

Given log2=0.3010 and log3=0.4771 the value of log6 is

Answer 1

log 6 can be written as

                                               

                     log {3×2}

                    we know log mn =log m+log n

so,   log{3×2}= log 3 + log 2

                      =0.4771+0.3010

          log 6= 0.7781

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Answer 2

we know the formula

$log(m) + log(n) = log(mn)$

$log(2) + log(3) = log(2 \times 3)$

$log(6) = log(2) + log(3)$

$log(6) = 0.3010 + 0.4771$

$log(6) = 0.7781$

So the answer will be:

$0.7781$

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