Question

Given: log8(5) = b. Express log4(10) in terms of b. Please solve this sum

Answer 1

$log_{8}(5) = b$
$\frac{1}{3} log_{2}(5) = b$
$log_{2}(5) = 3b$

$log_{4}(10)$
=>
$\frac{1}{2} log_{2}(2 \times 5)$
=>
$\frac{1}{2} log_{2}(2) + \frac{1}{2} log_{2}(5)$
=>
$\frac{1}{2} + \frac{3b}{2}$
=>
$\frac{1 + 3b}{2}$