Question

given log87.5=1.9421 find no. of digits in (8.75)^20

Answer 1

answer

the number of digits in (8.75)^20 =30

explanation

X = (875)^10 = (87.5 x 10)^10

X = (875)^10 = (87.5 x 10)^10Therefore, log10(X) = 10(log10(87.5 + 1))

X = (875)^10 = (87.5 x 10)^10Therefore, log10(X) = 10(log10(87.5 + 1))= 10(1.9421 + 1)

X = (875)^10 = (87.5 x 10)^10Therefore, log10(X) = 10(log10(87.5 + 1))= 10(1.9421 + 1)= 10(2.9421) = 29.421

X = (875)^10 = (87.5 x 10)^10Therefore, log10(X) = 10(log10(87.5 + 1))= 10(1.9421 + 1)= 10(2.9421) = 29.421X = antilog(29.421)

X = (875)^10 = (87.5 x 10)^10Therefore, log10(X) = 10(log10(87.5 + 1))= 10(1.9421 + 1)= 10(2.9421) = 29.421X = antilog(29.421)Therefore, number of digits in X = 30.

hope it helps you!!