given logx=y, express 10^3y-2 in terms of x
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Answered by
0
Answer:
Given logx=m+n,logy=m−n
log
y
2
10x
=log10+logx−2logy=log10+m+n−2(m−n)=log10+3n
Answered by
2
Answer:
given log y2
Step-by-step explanation:
log y2 10 =10xLog 10x+logx-2logy=log10+m+ n-2(m-n) =log1 0+3n
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