Question

Given <POR=3x and <QOR = 2x+10. If POQ is a straight line then the value of x is ….
A. 30⁰
B. 34⁰
C. 36⁰
D. 40⁰​

Answer 1

Given ∠POR = 3x and ∠QOR =2x+10°. If ∠POQ is a straight line, then the value of x is  34°

Option B is correct.

Given,

∠ POR = 3x

∠ QOR = 2x + 10°

∠ POQ is a straight line

⇒∠ POQ = 180°

But, we have,

∠ POR + ∠ QOR = ∠ POQ

3x + 2x + 10° = 180°

3x + 2x = 180° - 10°

5x = 170°

x = 34°

Answer 2

Answer:

Hope it helps

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