Question

Given :-
Lucas goes to an ice cream shop and buys two cones for $3.75 each. He hands  the cashier a $10 bill.
To Find :-
Change he will get back
Solution :-
Cost of 2 ice cream = 3.75  × 2
Cost of 2 ice cream = 7.5

Change given back = 10 - 7.5

Change given back = 2.5
​

Answer 1

Answer:

given,

given,the area of square is=5184m2

given,the area of square is=5184m2Sxs=5184

given,the area of square is=5184m2Sxs=5184s?=5184

given,the area of square is=5184m2Sxs=5184s?=5184s=v5184

given,the area of square is=5184m2Sxs=5184s?=5184s=v5184s=72

given,the area of square is=5184m2Sxs=5184s?=5184s=v5184s=72according to problem,

given,the area of square is=5184m2Sxs=5184s?=5184s=v5184s=72according to problem,I=2x

given,the area of square is=5184m2Sxs=5184s?=5184s=v5184s=72according to problem,I=2xb=x

given,the area of square is=5184m2Sxs=5184s?=5184s=v5184s=72according to problem,I=2xb=xwe know that,

given,the area of square is=5184m2Sxs=5184s?=5184s=v5184s=72according to problem,I=2xb=xwe know that,perimeter of square=perimeter of

given,the area of square is=5184m2Sxs=5184s?=5184s=v5184s=72according to problem,I=2xb=xwe know that,perimeter of square=perimeter ofrectangle

given,the area of square is=5184m2Sxs=5184s?=5184s=v5184s=72according to problem,I=2xb=xwe know that,perimeter of square=perimeter ofrectangle4s-2(1+b)

given,the area of square is=5184m2Sxs=5184s?=5184s=v5184s=72according to problem,I=2xb=xwe know that,perimeter of square=perimeter ofrectangle4s-2(1+b)4x72=2(2x+x)

given,the area of square is=5184m2Sxs=5184s?=5184s=v5184s=72according to problem,I=2xb=xwe know that,perimeter of square=perimeter ofrectangle4s-2(1+b)4x72=2(2x+x)288=6x

given,the area of square is=5184m2Sxs=5184s?=5184s=v5184s=72according to problem,I=2xb=xwe know that,perimeter of square=perimeter ofrectangle4s-2(1+b)4x72=2(2x+x)288=6xx=288/6

given,the area of square is=5184m2Sxs=5184s?=5184s=v5184s=72according to problem,I=2xb=xwe know that,perimeter of square=perimeter ofrectangle4s-2(1+b)4x72=2(2x+x)288=6xx=288/6x=48

given,the area of square is=5184m2Sxs=5184s?=5184s=v5184s=72according to problem,I=2xb=xwe know that,perimeter of square=perimeter ofrectangle4s-2(1+b)4x72=2(2x+x)288=6xx=288/6x=48from problem,

given,the area of square is=5184m2Sxs=5184s?=5184s=v5184s=72according to problem,I=2xb=xwe know that,perimeter of square=perimeter ofrectangle4s-2(1+b)4x72=2(2x+x)288=6xx=288/6x=48from problem,I=2x

given,the area of square is=5184m2Sxs=5184s?=5184s=v5184s=72according to problem,I=2xb=xwe know that,perimeter of square=perimeter ofrectangle4s-2(1+b)4x72=2(2x+x)288=6xx=288/6x=48from problem,I=2x=2x48

given,the area of square is=5184m2Sxs=5184s?=5184s=v5184s=72according to problem,I=2xb=xwe know that,perimeter of square=perimeter ofrectangle4s-2(1+b)4x72=2(2x+x)288=6xx=288/6x=48from problem,I=2x=2x48=96

given,the area of square is=5184m2Sxs=5184s?=5184s=v5184s=72according to problem,I=2xb=xwe know that,perimeter of square=perimeter ofrectangle4s-2(1+b)4x72=2(2x+x)288=6xx=288/6x=48from problem,I=2x=2x48=96b=x

given,the area of square is=5184m2Sxs=5184s?=5184s=v5184s=72according to problem,I=2xb=xwe know that,perimeter of square=perimeter ofrectangle4s-2(1+b)4x72=2(2x+x)288=6xx=288/6x=48from problem,I=2x=2x48=96b=x=48

given,the area of square is=5184m2Sxs=5184s?=5184s=v5184s=72according to problem,I=2xb=xwe know that,perimeter of square=perimeter ofrectangle4s-2(1+b)4x72=2(2x+x)288=6xx=288/6x=48from problem,I=2x=2x48=96b=x=48therefore length is 96

given,the area of square is=5184m2Sxs=5184s?=5184s=v5184s=72according to problem,I=2xb=xwe know that,perimeter of square=perimeter ofrectangle4s-2(1+b)4x72=2(2x+x)288=6xx=288/6x=48from problem,I=2x=2x48=96b=x=48therefore length is 96breadth is 48

given,the area of square is=5184m2Sxs=5184s?=5184s=v5184s=72according to problem,I=2xb=xwe know that,perimeter of square=perimeter ofrectangle4s-2(1+b)4x72=2(2x+x)288=6xx=288/6x=48from problem,I=2x=2x48=96b=x=48therefore length is 96breadth is 48area of rectangle = |x b

given,the area of square is=5184m2Sxs=5184s?=5184s=v5184s=72according to problem,I=2xb=xwe know that,perimeter of square=perimeter ofrectangle4s-2(1+b)4x72=2(2x+x)288=6xx=288/6x=48from problem,I=2x=2x48=96b=x=48therefore length is 96breadth is 48area of rectangle = |x b= 96 x 48

given,the area of square is=5184m2Sxs=5184s?=5184s=v5184s=72according to problem,I=2xb=xwe know that,perimeter of square=perimeter ofrectangle4s-2(1+b)4x72=2(2x+x)288=6xx=288/6x=48from problem,I=2x=2x48=96b=x=48therefore length is 96breadth is 48area of rectangle = |x b= 96 x 48=4608 m?

Answer 2

Answer:

element or compound that takes part in a chemical reaction