Question

given mass of earth is 6 *10 24 kg radius of the earth is 6.4 *10 6 m. calculate the force of attraction experienced by a man of mass 50 kg?

Answer 1

Answer:

Explanation:

G=6.7*10^-11 nm²/kg²

m1=6*10^24 kg

m2=50 kg

radius=6.4*10^6m

F=G*m1*m2/r²

F=6.7*10^-11*6.4*10^24*50/6.4*10^6m

F=6.7*6.4*50*10^-11+24/6.4*10^6

f=