Given, mass of the moon is 1/81 of the mass of the earth and its radius is 1/4 of the earth. If escape
velocity on the earth surface is 11.2 km/s, the value of the same on the surface of the moon is:
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Answer:
ANSWER
v
e
=
R
e
2GM
e
v
m
=
4
R
e
2G
81
M
e
=
9
2
v
e
=2/9×11.2kms
−1
=2.5kms
Explanation:
ANSWER
v
e
=
R
e
2GM
e
v
m
=
4
R
e
2G
81
M
e
=
9
2
v
e
=2/9×11.2kms
−1
=2.5kms
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