Question

Given, mass of the moon is 1/81 of the mass of the earth and its radius is 1/4 of the earth. If escape
velocity on the earth surface is 11.2 km/s, the value of the same on the surface of the moon is:

Answer 1

Answer:

ANSWER

v

e

=

R

e

2GM

e

v

m

=

4

R

e

2G

81

M

e

=

9

2

v

e

=2/9×11.2kms

−1

=2.5kms

Explanation:

ANSWER

v

e

=

R

e

2GM

e

v

m

=

4

R

e

2G

81

M

e

=

9

2

v

e

=2/9×11.2kms

−1

=2.5kms