Question

Given,
Masses=5kg,2kg
So,
Let x be the extension when t kg leaves the contact.
kx=2g
x= k
2g
​ = 2
1
​ m
So, by the law of conservation of energy for 5kg mass
mgx= 2
1
​ (x 2
+mv 2
)
= 2
1
​ x 2
+ 2
mv 2
​ ⇒ 2
2mgx−x 2
​ = 2
mv 2
​ v= 2gx− m
kx 2
​ ​ = 2× 2
101
​ − 5
40
​ × 4
1
​ ​ =2 2
​ m
THus, the value of x is =2 2
​ m

Answer 1

Answer:

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Step-by-step explanation:

abcdefghijklmnopqrstuvwxyz

abcdefghijklmnopqrstuvwxyz

abcdefghijklmnopqrstuvwxyz

abcdefghijklmnopqrstuvwxyz

abcdefghijklmnopqrstuvwxyz