given n= 12, L= 71,d =3 in an ap find a and S
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hi frnd
L=a+(n-1)d
71=a+(12-1)3=a+33
a=71-33=38
S=n/2(a+L)=12/2(38+71)=6(109)=654
hence a=38 and S=654
L=a+(n-1)d
71=a+(12-1)3=a+33
a=71-33=38
S=n/2(a+L)=12/2(38+71)=6(109)=654
hence a=38 and S=654
vyas03:
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