Question

given n=512 and k=10, the function should return 972 . the result can be obtained by increasing the first digit of n four times aand the second digit six times

Answer 1

Answer:

def solution(N,K):

   res=[int(i) for i in str(N)]

   # print(res)

   

   kb = K

   new = []

   

   for i in res:

       dum = i

       while(dum!=9):

           if kb == 0:

               break;

           else:

               dum+=1

               kb-=1

       # print(dum)

       new.append(dum)

   print(new)

   

   

solution(512,10)

Explanation:

Answer 2

Answer:

#include <iostream>

using namespace std;

int main() {

   int i, n=512, k=10, c=1;

   int a[3];

   for(i=2;i>=0;i--)

   {

       a[i]= n%10;

       n=n/10;

   }

   while(c<5)

   {

       a[0]+=1;

   }

   c=k-c;

   while(c<7)

   {

       a[1]+=1;

   }

   for(i=0;i<3;i++)

   {

   cout<<a[i];

   }

   return 0;

}

Explanation:

• We start by declaring the necessary variables.
• Next, separate the digits of 512 and store them in an array.
• Take the first digit and increment its value four times.
• Then take the second number and increment its value six times.
• Print the new number as the output.

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