Question

Given n(A) = 29, n(B) = 27, n(AUB) = 47. Find
n(A n B)
n(A-B)​

Answer 1

Given :

n(A) = 29

n(B) = 27

n(AUB) = 47

=> n(AUB) = n(A) + n(B) - n(A∩B)

47 = 29+27 - n(A∩B)

47 = 56 - n(A∩B)

n(A∩B) = 56 - 47

n(A∩B) = 9

=> n(A-B) = n(A) - n(A∩B)

n(A-B) = 29 - 9

n(A-B) = 20

Hope you got the answer for the question