Given n(A-B)=18, n(AuB)=70 and n(AnB)=25. Find n(B) show your work
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Given, n(A - B) =18, n(A∪B) =70, n(A n B) =25
So, n(A) - (AnB) = 18
n(A) = n(A-B) + n(AnB)
= 18 +25
= 43
n(A) + n(B) - n(AnB) = 70
= 43 + n(B) - 25 = 70
n(B) - 25 = 70 -43
n(B) = 25 +27
= 52.
Hope this helps!
So, n(A) - (AnB) = 18
n(A) = n(A-B) + n(AnB)
= 18 +25
= 43
n(A) + n(B) - n(AnB) = 70
= 43 + n(B) - 25 = 70
n(B) - 25 = 70 -43
n(B) = 25 +27
= 52.
Hope this helps!
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