given n(p(A))=512 n(p(r)) = 64 and n(A intersection B)=5 find n(A union B)
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Step-by-step explanation:
n(P(A)) = 512 = 2⁹
n(A) = 9
and
n(P(B)) = 64 = 2⁶
n(B) = 6
Given = n(A∩B) = 5
By formula
n(A)+n(B)-n(A∩B) = n(AUB)
n(AUB) = 9+6-5 = 10
Hope it helped!
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