Question

given numbers 6,7,18,22.what number must be subtracted from each of the following numbers,so that they will be in proportion​

Answer 1

Step-by-step explanation:

1st no.=6-x

2nd no.=7-x

3rd no.=18-x

4th no.=22-x

A.T.S

(6-x):(7-x)::(18-x):(23-x)

6-x/7-x=18-x/22-x

(6-x)(22-x)=(7-x)(18-x)

132-28x+x2=126-25x+x2

-28x+25x=126-132

-3x=-6

x=6/3

x=2

Answer 2

The required number is 2.

Step-by-step explanation:

Given : Numbers 6,7,18,22.

To find : What number must be subtracted from each of the following numbers,so that they will be in proportion​ ?

Solution :

Let the number subtracted be 'x'.

So, the numbers will became 6-x,7-x,18-x and 22-x.

When they are in proportion,

$6-x:7-x::18-x:22-x$

$\frac{6-x}{7-x}=\frac{18-x}{22-x}$

Cross multiply,

$(6-x)(22-x)=(18-x)(7-x)$

$132-6x-22x+x^2=126-18x-7x+x^2$

$-3x=-6$

$x=\frac{-6}{-3}$

$x=2$

Therefore, the required number is 2.

#Learn more

What number must be subtracted from each of the number 31,19,13,10 so that they are in proportion

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