Question

Given : O is the centre of the circle.Radius is 10cm. OC perpendicular AB. OC = 6cm. Find: /(AB)

Answer 1

Answer:

Step-by-step explanation:

OC=6cm

JOIN OA

OA=10cm

perpendicular from centre of the circle bisects the chord

hence,AC=BC

using pythagoras theorem in triangleOAC

AC²=OA²-OC²

AC=8cm

AB=AC+BC

AC=BC    PROVED

8=BC

HENCE AB=8+8=16cm

Answer 2

Answer:

Given OA=10cm

OC=6cm

∠OCA= 90

by Pythagoras theorem

AC=8cm

We know that perpendicular from centre of circle bisects the chord

Therefore AB=2AC

AB=16cm