Question

Given:
O2(g) - 20(g)
AH = -498.4 kJ/mol
NO(g) + O3(g) - NO2(g) + O2(g)
AH = -200.0 kJ/mol
302(g) → 203(g)
AH = +285.4 kJ/mol
What is the standard reaction enthalpy for the following reaction?
NO2(g) → NO(g) + O(g)
a. +306 kJ/mol
b. +413 kJ/mol
c. +555 kJ/mol
d. +592 kJ/mol
e. +355 kJ/mol​

Answer 1

Explanation:

2 O3 (g) → 3 O2 (g) ΔH = -427 kJ

O2 (g) → 2O (g) ΔH = 495 kJ

NO (g) + O3 (g) → NO2 (g) + O2 (g) ΔH = -199 kJ

calculate ΔH for the reaction

NO (g) + O (g) → NO2 (g)

Answer 2

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ΔH° = +555 kJ/mol