Question

given one of the roots of the quadratic equation x² - px + 12 = 0 is 3, calculate the value of p

please show step by step​

Answer 1

Answer:

One root of the equation x

2

+px+12=0 is 4

⇒16+4p+12=0

∴p=−7

as x

2

+px+q=0 has equal roots.

b

2

=4ac ⇒p

2

=4q

∴q=

4

49

HENCE ANSWER IS 49/4

Step-by-step explanation:

BY TEJAS KULKARNI PLEASE FOLLOW

Answer 2

Step-by-step explanation:

p(x)=x

${x}^{2} - px + 12 = 0 \\ p(3) =0 \\ = 3 { }^{2} - p(3) + 12 = 0 \\ \: \: = 9 - 3p + 12 = 0 \\ 21 - 3p = 0 \\ 3(7 - p) = 0 \\ 7 - p = 0 \\ \\ 7 = p$

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