Math, asked by jasonvoorheees13, 3 months ago

Given P(A) = 0.4, P(B) = 0.5 and
P(AUB)=0.9,then: *​

Answers

Answered by KrishnaSanayram8
2

Answer:  P (AuB) =P(A)+(B) - P(A)×P(B) Or 0.9=0.6+P(B) - 0.6 P (B) Or ... 0.6 + 0.4 P(B). ... of probability to occur, then can I say that the probability of events 'a', 'b' and 'c' occur is 0.5^3? ... given that the A and B are independent events i.e; P(A n B)=0.

Step-by-step explanation: i hope this helps you mark me as brainliest thank you

Answered by shubhamjaiswal4294
0

Step-by-step explanation:

check your answer clearly okkk

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