Question

Given P(x) = 12x² +8x-9 and Q(x) = 9x² + 14x + 29. Let the sum of the roots of P(x) = 0 and Q(x)=0 are a and b, respectively. The sum of the roots of R(x) = ax² + bx + ab, is​

Answer 1

Step-by-step explanation:

a = -8/12 b = -14/9 now find r(x)..

then it's sum of roots = -b/a = -14/9÷ -8/12 = 14/9× 3/-2 = -7/3