Given: P(x)=x^3-8x^2+X+42 Find the sum of the roots
Answers
Answer:
Step-by-step explanation:Rearrange:
Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :
0-(x^3-8*x^2+x+42)=0
Step by step solution :
STEP
1
:
Equation at the end of step 1
0 - ((((x3) - 23x2) + x) + 42) = 0
STEP
2
:
STEP
3
:
Pulling out like terms
3.1 Pull out like factors :
-x3 + 8x2 - x - 42 =
-1 • (x3 - 8x2 + x + 42)
Checking for a perfect cube :
3.2 x3 - 8x2 + x + 42 is not a perfect cube
Trying to factor by pulling out :
3.3 Factoring: x3 - 8x2 + x + 42
Thoughtfully split the expression at hand into groups, each group having two terms :
Group 1: x + 42
Group 2: x3 - 8x2
Pull out from each group separately :
Group 1: (x + 42) • (1)
Group 2: (x - 8) • (x2)
Bad news !! Factoring by pulling out fails :
The groups have no common factor and can not be added up to form a multiplication.
Answer:
See the solution in the photo above!
#HOPE IT HELPS
