Question

Given P(x)=x²-2x+5 then find value of P(0) and P(1).​

Answer 1

${\large{\bf{\clubs{\red{\underline{Given :}}}}}}$

Given:

${\sf{{{p(x) = {x}^{2} - 2x + 5 }}}}$

By taking x as :

${\bf{x= 0}}$

${\bf{x = 1}}$

￣￣￣￣￣￣￣￣￣￣￣￣

${\large{\bf{\clubs{\blue{\underline{Solution :}}}}}}$

First,

${\sf{\green{X = 0}}}$

${\sf{\purple{{p(x) = {x}^{2} - 2x + 5 }}}}$

${\sf{\purple{{p(0) = {0}^{2} - 2 \times 0 + 5 }}}}$

${\sf{\purple{{p(0) = 0 - 2 \times 0 - 5}}}}$

${\sf{\purple{{p(0) = 0 \times 0}}}}$

${\sf{\purple{{p(0) = 0}}}}$

Than ,

${\sf{\green{X = 1}}}$

${\sf{\purple{{p(x) = {x}^{2} - 2x + 5 }}}}$

${\sf{\purple{{p(1) = {1}^{2} - 2 \times 1 + 5 }}}}$

${\sf{\purple{{p(1) = 1 - 2 \times 6}}}}$

${\sf{\purple{{p(1) = - 1 \times 6}}}}$

${\sf{\purple{{p(1) = - 6}}}}$

Hence,

${\mathfrak{\green{The \: value \: of \: 0 \: in \: this \: polynomial \: is \: 0.}}}$

${\mathfrak{\green{The \: value \: of \: 1 \: in \: this \: polynomial \: is \: -6.}}}</p><p>$

￣￣￣￣￣￣￣￣￣￣￣￣

${\large{\fcolorbox{red}{green}{\underline{\blue{itzNobita5}}}}}$

Answer 2

Answer:

sol:- if p(0) then p(0)= (0)^2-2×0+5=5

and if p(1) then p(1)= (1)^2-2×1+5=1-2+5= -1+5= 4