Question

given parallelogram ABCD in which diagonals AC and BD intersect at M. prove : M is midpoint of LN​

Answer 1

Answer:

Proof:Diagonals of parallelogram bisect each other

MD=MB

Also ∠ADB=∠DBN (Alternate ∠S)

∠DML=∠BMN (ert.opp.∠S)

△DML=△BMN

LM=MN

M is mid-point of LN.

Hence proved.

Answer 2

Answer:

Refer to the attachment Army-shii

Step-by-step explanation:

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