Question

Given perimeter of rectangle is 170 and its breadth exceeds by 15 mts then find its length

Answer 1

Let the breadth be x m and Length be ( x + 15 ) m



Perimeter = 170


$\mathbf{we \: \: know \: \: \: \: perimeter \: = 2(length \: + breadth}$

Hence,

2( x + x + 15 ) = 170

=> 2x + 15 = 170 / 2

=> 2x = 85 - 15

=> x = 70 / 2

=> x = 35





Hence, length is ( x + 15 ) = ( 35 + 15 ) = 50 m

Answer 2

Here is the answer mate
Give perimeter of rectangle =2(l+b)
Then let length be x and breadth be x+15
So 2(x+x+15)=170
4x+30=170
by substituting the values
170-30
140=4x
x=140/4
therefore length =27.5
and breadth =42.5