given piece of wire length L cross section area a and resistance R is stretched uniformly to a wire of length 2L what will be the new resistance
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Answer:
it will be twice the earlier
Explanation:
R=rho*l/a
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Explanation:
this question basically requires an understanding of volume.
we know volume = (length) x (area of cross section )
(So obviously length increases to twice then obviously area of cross section decreases to half )
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