Math, asked by aryansharma6085, 10 months ago

. Given points A(1, 5), B(-3, 7) and C(15, 9).
(i) Find the equation of a line passing through the mid-point of AC and the point B.
(ii) Find the equation of the line through C and parallel to AB
iii) The lines obtained in parts (i) and (ii) above, intersect each other at a point P. Find
the co-ordinates of the point P.​

Answers

Answered by amitnrw
1

Given : points A(1, 5), B(-3, 7) and C(15, 9).

To Find :  

the equation of a line passing through the mid-point of AC and the point B.

equation of the line through C and parallel to AB

Solution:

A(1, 5)  and C(15, 9).

Mid point of A and C  = ( 1 + 15)/2 , ) (5 + 9)/2

= 8 , 7

B(-3, 7)

(8 , 7)

slope  =   0

y - 7   = 0 (x - 8)

=> y = 7

y = 7 is the equation of a line passing through the mid-point of AC and the point B.

equation of the line through C and parallel to AB

A(1, 5) B(-3, 7)  

Slope =  (7 - 5)/(-3 - 1)  = 2/(-4) = -1/2

C(15, 9).

y  - 9 = (-1/2)(x - 15)

=> 2y - 18 = -x + 15

=> x + 2y = 33

y = 7

x + 2y = 33

=> x = 19

( 19 , 7)

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Answered by Anonymous
2

ANSWER ⤵️

Given : points A(1, 5), B(-3, 7) and C(15, 9).

To Find :  

the equation of a line passing through the mid-point of AC and the point B.

equation of the line through C and parallel to AB

Solution:

A(1, 5)  and C(15, 9).

Mid point of A and C  = ( 1 + 15)/2 , ) (5 + 9)/2

= 8 , 7

B(-3, 7)

(8 , 7)

slope  =   0

y - 7   = 0 (x - 8)

=> y = 7

y = 7 is the equation of a line passing through the mid-point of AC and the point B.

equation of the line through C and parallel to AB

A(1, 5) B(-3, 7)  

Slope =  (7 - 5)/(-3 - 1)  = 2/(-4) = -1/2

C(15, 9).

y  - 9 = (-1/2)(x - 15)

=> 2y - 18 = -x + 15

=> x + 2y = 33

y = 7

x + 2y = 33

=> x = 19

( 19 , 7)

☺️

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