Math, asked by vallabhgavali061, 6 hours ago

Given positive integers x andy such that mytn, where manda are unique interess then. x =​

Answers

Answered by kashvichaurasia819
0

Answer:

Given: . Notice that since equals to some perfect square (x^2) then must complete the odd powers of other multiples to even numbers (remember perfect square has even powers of its primes), so the least value of is (y is a multiple of 14). So, we need one more 2 for in order it to be divisible by 28.

(1) x is divisible by 4 --> is divisible by 4^2=16=2^4, since 350 has only one 2 then must have the remaining 2^3, so we have that is divisible by 2^3*7=2*28. Sufficient.

(2) x^2 is divisible by 28 --> since the least value of is then , so we already knew that is divisible by 28. Not sufficient.

Step-by-step explanation:

Kashuuu~

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