Question

Given, potential difference V=(8+-0.5)volt and current I=(2+-0.2)A. The value of resistance R is ?​

Answer 1

Answer:

Hey mate here is your answer

v=(100+-5)a

I=(10+-0.2)a

R=V/I =100/10=10Ω

ΔR/R=+_[ ΔV/V+ ΔI/I]

=+_[5/100+0.2/10]

=+_[7/100]

=+_0.07

ΔR=R*0.07

=+_0.07*10

=0.7 ohms

Percentage ΔR/R*100=+_0.07*100=+_7 percent

Hope this helps

Answer 2

Given,

Potential difference V=(8+-0.5)volt and current I=(2+-0.2)A.

To Find,

The value of resistance R is?​

Solution,

We can solve the question as follows:

It is given that the potential difference is V=(8+-0.5)volt and the current is I=(2+-0.2)A. We have to find the value of the resistance R.

$Potential\: difference, V = (8 + -0.5)\: V$

$Current, I = (2 + -0.2)A$

According to Ohm's Law, the potential difference across a conductor is equal to the current multiplied by the resistance through it.

$V = IR$

Substituting the values in the above formula,

$8 = 2*R$

$R = \frac{8}{2} = 4\: Ohms$

Now, we will find the percentage error in the resistance.

While finding the percentage error, we will add the errors.

The formula to find the percentage error in the resistance is:

$\frac{delta\: R}{R} = \frac{delta\: V}{V} + \frac{delta\: I}{I}$

Substituting the values,

$\frac{delta\: R}{R} = \frac{0.5}{8}+ \frac{0.2}{2}$

$\frac{delta\: R}{R} = \frac{1}{16} +\frac{1}{10}$

$\frac{delta\: R}{R} = \frac{10 + 16}{160}$

$\frac{delta\: R}{R} = \frac{26}{160}$

To find the percent, we will multiply by 100,

$Error\: in\: resistance = \frac{26}{160} *100$

                               $= 0.1625*100$

                               $= 16.25\:$%

Hence, the resistance R is equal to (4 +- 16.25) Ohms.