Question

Given potential difference v=[8+-0.5]volt and current I =[2+-0.2]A.What is the value of resistance?

Answer 1

Given:

• Voltage = [8±0.5]
• Current = [2±0.2]

To find:

• The value of resistance = ?

ExPlanation:

The voltage that we have is actually of the form $v \pm \Delta{v}$ and the current us of the form $l \pm \Delta{l}$, so from ohms law we have,

V = lR

V/l = R

• Now, put the values of V and l in the equation

8/2 = R

4 = R

Now, resistance equaivalent will be,

= $\dfrac{\Delta{R}}{R}$ = $\dfrac{\Delta{V}}{V}$ + $\dfrac{\Delta{l}}{l}</p><p>$

= $\dfrac{\Delta{R}}{R}$ = $\dfrac{0.5}{8}$ + $\dfrac{0.2}{2}$

= $\dfrac{\Delta{R}}{R}$ = $\dfrac{0.5 + 0.8}{8}$

= $\dfrac{\Delta{R}}{R}$ = $\dfrac{1.3}{8}$

= $\dfrac{\Delta{R}}{R}$ = 0.16

Now, write the resistance in the form of $R \pm \Delta{R}$ which will be $4 \pm 0.16$

Hope it helps! ^^