Math, asked by serenityakers, 3 months ago

Given
\qquad m \angle ABDm∠ABDm, angle, A, B, D is a straight angle.
\qquad m \angle ABC = 2x + 50^\circm∠ABC=2x+50

m, angle, A, B, C, equals, 2, x, plus, 50, degrees
\qquad m \angle CBD = 6x + 2^\circm∠CBD=6x+2

m, angle, C, B, D, equals, 6, x, plus, 2, degrees
Find m\angle CBDm∠CBDm, angle, C, B, D:

Answers

Answered by nanditasarkar3006
5

Answer:

Given:

M ∠ ABD is a straight angle. ∠ ABC = 2x + 50∘ ∠ CBD = 6x + 2∘  

To find:

Find m ∠ CBD

Solution:

From given, we have,

∠ ABD = 180°

∠ ABC = 2x + 50∘ ∠ CBD = 6x + 2∘  

Consider the attached figure while going through the following steps.

∠ ABC + ∠ CBD = 2x + 50° + 6x + 2°

180° = 8x + 52°

180° - 52° = 8x

128° = 8x

∴ x = 16°

Now consider,

∠ ABC = 2x + 50° = 2(16) + 50 = 82°

∠ CBD = 6x + 2° = 6(16) + 2 = 98°

∴ ∠ ABC = 82°  and ∠ CBD =  98°

Answered by ITZANIRUTH
3

A

B

D

=

=

49

C

B

D

=

28

Explanation:

A

B

C

=

A

B

D

+

C

B

D

77

=

(

3

x

+

22

)

+

(

5

x

17

)

77

=

8

x

+

5

8

x

=

77

5

=

72

x

=

72

8

=

9

A

B

D

=

(

3

(

9

)

+

22

)

=

49

C

B

D

=

(

5

(

9

)

17

)

=

28

Check:

A

B

C

=

A

B

D

+

C

B

D

=

77

=

49

+

28

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