Given
\qquad m \angle AOC = 104^\circm∠AOC=104
∘
m, angle, A, O, C, equals, 104, degrees
\qquad m \angle AOB = 7x + 30^\circm∠AOB=7x+30
∘
m, angle, A, O, B, equals, 7, x, plus, 30, degrees
\qquad m \angle BOC = 9x + 42^\circm∠BOC=9x+42
∘
m, angle, B, O, C, equals, 9, x, plus, 42, degrees
Find m\angle BOCm∠BOCm, angle, B, O, C:
Answers
Answered by
5
∠AOB = 40°
∠BOC = 68°
Step-by-step explanation:
∠AOC = 108°
∠AOB = 3x + 4°
∠BOC = 8x - 28°
∠AOC = ∠AOB + ∠BOC
=> 108 = 3x + 4 + 8x - 28
=> 132 = 11x
=> x = 12
∠AOB = 3* 12 + 4 = 40°
∠BOC = 8*12 - 28° = 68°
∠AOB = 40°
∠BOC = 68°
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Answered by
0
Answer:
108
Step-by-step explanation:
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