Math, asked by IMJustMe, 2 months ago

Given
\qquad m \angle QPSm∠QPSm, angle, Q, P, S is a straight angle.
\qquad m \angle QPR = 7x - 4^\circm∠QPR=7x−4

m, angle, Q, P, R, equals, 7, x, minus, 4, degrees
\qquad m \angle RPS = 9x - 40^\circm∠RPS=9x−40

m, angle, R, P, S, equals, 9, x, minus, 40, degrees
Find m\angle QPRm∠QPRm, angle, Q, P, R:

Answers

Answered by man4161
3

Step-by-step explanation:

qquad m \angle QPSm∠QPSm, angle, Q, P, S is a straight angle.

\qquad m \angle QPR = 7x - 4^\circm∠QPR=7x−4

m, angle, Q, P, R, equals, 7, x, minus, 4, degrees

\qquad m \angle RPS = 9x - 40^\circm∠RPS=9x−40

m, angle, R, P, S, equals, 9, x, minus, 40, degrees

Find m\angle QPRm∠QPRm, angle, Q, P, R:

qquad m \angle QPSm∠QPSm, angle, Q, P, S is a straight angle.

\qquad m \angle QPR = 7x - 4^\circm∠QPR=7x−4

m, angle, Q, P, R, equals, 7, x, minus, 4, degrees

\qquad m \angle RPS = 9x - 40^\circm∠RPS=9x−40

m, angle, R, P, S, equals, 9, x, minus, 40, degrees

Find m\angle QPRm∠QPRm, angle, Q, P, R:

qquad m \angle QPSm∠QPSm, angle, Q, P, S is a straight angle.

\qquad m \angle QPR = 7x - 4^\circm∠QPR=7x−4

m, angle, Q, P, R, equals, 7, x, minus, 4, degrees

\qquad m \angle RPS = 9x - 40^\circm∠RPS=9x−40

m, angle, R, P, S, equals, 9, x, minus, 40, degrees

Find m\angle QPRm∠QPRm, angle, Q, P, R:.

qquad m \angle QPSm∠QPSm, angle, Q, P, S is a straight angle.

\qquad m \angle QPR = 7x - 4^\circm∠QPR=7x−4

m, angle, Q, P, R, equals, 7, x, minus, 4, degrees

\qquad m \angle RPS = 9x - 40^\circm∠RPS=9x−40

m, angle, R, P, S, equals, 9, x, minus, 40, degrees

Find m\angle QPRm∠QPRm, angle, Q, P, R:

Attachments:
Answered by nosleep
23

Answer:

94

Step-by-step explanation:

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