Math, asked by config6187, 5 months ago

Given: Right △ABC as shown where CD is an altitude of the triangle
Prove: a2 + b2 = c2
Consider the diagram and the paragraph proof below.
Given: Right △ABC as shown where CD is an altitude of the triangle
Prove: a2 + b2 = c2
Because △ABC and △CBD both have a right angle, and the same angle B is in both triangles, the triangles must be similar by AA. Likewise, △ABC and △ACD both have a right angle, and the same angle A is in both triangles, so they also must be similar by AA. The proportions and are true because they are ratios of corresponding parts of similar triangles. The two proportions can be rewritten as a2 = cf and b2 = ce. Adding b2 to both sides of first equation, a2 = cf, results in the equation a2 + b2 = cf + b2. Because b2 and ce are equal, ce can be substituted into the right side of the equation for b2, resulting in the equation a2 + b2 = cf + ce. Applying the converse of the distributive property

Answers

Answered by Anonymous
1

Because △ABC and △CBD both have a right angle, and the same angle B is in both triangles, the triangles must be similar by AA. Likewise, △ABC and △ACD both have a right angle, and the same angle A is in both triangles, so they also must be similar by AA

Answered by SmitaMissinnocent
3

Answer:

Pilavullakandi Thekkeparambil Usha is a retired Indian track and field athlete. She has been associated with Indian athletics since 1979. She is often called the "queen of Indian track and field".

Born: 27 June 1964 (age 56 years), Payyoli

Spouse: V Srinivasan (m. 1991)

Nickname(s): Golden Girl, Payyoli Express

Event(s): Sprints

Awards: Arjuna Award for Athletics, Padma Shri

Books: Golden Girl: The Autobiography of P.T. Usha

Children: Vignesh Ujjwal, Ujjwal Srinivasan

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