given right angled ∆ABC rigth angled B in wihch tan A =15÷8 and tanC = 8÷ 15 find the value of sin A cos C +cos A sinC
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3
Answer:
1
Step-by-step explanation:
since, the sum of the angles of a triangle is 180° and B is 90°, A + C is 90°
sinA.cosC + cosA.sinC
= sinA.sin(90°–C) + cosA.cos(90°–C)
= sinA.sinA + cosA.cosA
= sin²A + cos²A
= 1
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0
Answer:
q u e s t I o n I s w r o n g I t h I n k s o p l e a s e c o o r e ct
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