Question

Given right triangle MNL, what is the value of cos(M)?

Answer 1

Step-by-step explanation:

Triangle MNL

NL = Perpendicular

MN = Base

ML = Hypotenuse

Cos(M) = Base/hypotenuse

Cos(M) = MN/ML

Answer 2

The value of cos(M)=$\frac{4}{5}$

Step-by-step explanation:

In right triangle MNL

ML=25 units

NL=15 units

Angle N=90 degrees

$ML^2=NL^2+MN^2$

Using Pythagoras theorem

$(Hypotenuse)^2=(base)^2+(Perpendicular\;side)^2$

$(25)^2=(15)^2+MN^2$

$625=225+MN^2$

$MN^2=625-225=400$

$MN=\sqrt{400}=20units$

$Cos\theta=\frac{base}{hypotenuse}$

Using the formula

$cosM=\frac{MN}{ML}$

$cosM=\frac{20}{25}=\frac{4}{5}$

Hence, the value of cos(M)=$\frac{4}{5}$

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