Math, asked by Krishna9898, 2 months ago

Given :-
Rs. 10,000 is invested at 6%p.a. compounded annually for two years .
To Find :-
What will be the amount ?
Solution :-
~Here, we’re given the principal , rate and time for which the money is invested and we need to find the amount after the given time. We can easily find the amount by putting the values in it’s formula.

Here,

The principal ( P ) is Rs. 10,000
The rate ( R ) is 6 %
The time ( n ) is 2 years
The amount will be ( A )
As we know that formula of amount is ,

\sf \bullet \;\; A = P \bigg \{ 1 + \dfrac{R}{100} \bigg \}^{n}∙A=P{1+
100
R

}
n


By putting the values !

\sf \implies A = 10,000 \bigg \{ 1 + \dfrac{6}{100} \bigg \}^{2}⟹A=10,000{1+
100
6

}
2


\sf \implies A = 10,000 \bigg \{ \dfrac{106}{100} \bigg \}^{2}⟹A=10,000{
100
106

}
2


\sf \implies A = 10,000 \times \dfrac{106}{100} \times \dfrac{106}{100}⟹A=10,000×
100
106

×
100
106



\sf \implies A = 1 \times 106 \times 106⟹A=1×106×106

\sf \implies A = Rs. \; 11,236⟹A=Rs.11,236

Therefore,
The amount will be Rs. 11,236




HY GUYS PLEASE SOMEBODY EXPLAIN ME THIS SUM​

Answers

Answered by rose8120
0

Answer:

that's so simple you can solve it as they have given .

Step-by-step explanation:

Pls mark me as brainlist

Answered by ansh416659
0

Answer:

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