Given :-
Rs. 10,000 is invested at 6%p.a. compounded annually for two years .
To Find :-
What will be the amount ?
Solution :-
~Here, we’re given the principal , rate and time for which the money is invested and we need to find the amount after the given time. We can easily find the amount by putting the values in it’s formula.
Here,
The principal ( P ) is Rs. 10,000
The rate ( R ) is 6 %
The time ( n ) is 2 years
The amount will be ( A )
As we know that formula of amount is ,
\sf \bullet \;\; A = P \bigg \{ 1 + \dfrac{R}{100} \bigg \}^{n}∙A=P{1+
100
R
}
n
By putting the values !
\sf \implies A = 10,000 \bigg \{ 1 + \dfrac{6}{100} \bigg \}^{2}⟹A=10,000{1+
100
6
}
2
\sf \implies A = 10,000 \bigg \{ \dfrac{106}{100} \bigg \}^{2}⟹A=10,000{
100
106
}
2
\sf \implies A = 10,000 \times \dfrac{106}{100} \times \dfrac{106}{100}⟹A=10,000×
100
106
×
100
106
\sf \implies A = 1 \times 106 \times 106⟹A=1×106×106
\sf \implies A = Rs. \; 11,236⟹A=Rs.11,236
Therefore,
The amount will be Rs. 11,236
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Answers
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Answer:
that's so simple you can solve it as they have given .
Step-by-step explanation:
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Answer:
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