Given sec 0= 13/12 (in fraction) calculate all other trigonometric ratios. Sol. Let us have a right ΔABC in which ∠B = 90°
GOOD ANSWERS = GOD WILL GIVE YOU A GIFT+YOU WILL SCORE BETTER MARKS
BAD OR WRONG ANSWERS= GOD WILL PUNISH YOU + YOU WILL NOT SCORE BETTER MARKS IN EXAM
(CLASS 10,CBSE)
Answers
Answered by
0
Answer:
Answer
Let △ABC be right angled triangle (right angled at B)
secQ=
AB
AC
=
12
13
Let AC=13x and AB=12x
AC
2
=AB
2
+BC
2
BC
2
=AC
2
−AB
2
x
2
=169−144
x
2
=25
x=
25
=5
sinQ=
AC
BC
=
13x
5x
=
13
5
cosQ=
AC
AB
=
13
12
tanQ=
AB
BC
=
12x
5x
=
12
5
cotQ=
tanQ
1
=
12
5
1
=
5
12
cosec Q=
BC
AC
=
5x
13x
=
5
13
solution
Attachments:
Anonymous:
nhi answer wrong ha
appne can or cot ki value to btai hi nhi
Similar questions