Question

Given secθ = 12/13, calculate all other trigonometric ratios.

Answer 1

Step-by-step explanation:

Let ΔABC be a right-angled triangle, right-angled at B.

We know that sec θ = OP/OM = 13/12   (Given)

Let OP be 13k and OM will be 12k where k is a positive real number.

By Pythagoras theorem we get, OP2 = OM2 + MP2 (13k)2 =

(12k)2 + MP2 169k2 - 144k2 = MP2 MP2

= 25k2 MP = 5 Now, sin θ = MP/OP = 5k/13k = 5/13 cos θ = OM/OP = 12k/13k = 12/13 tan θ = MP/OM = 5k/12k = 5/12 cot θ = OM/MP = 12k/5k = 12/5 cosec θ = OP/MP = 13k/5k = 13/5

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Answer 2

Answer:

Good evening....

Hope it helps....