given sec A = 13/12 then find the value of sin A
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Given:
To find :
Value of sin A
Solution:
As we know that,
sec A = 1/cos A
So,
sec A = 13/12 = 1/cos A
=> cos A = 12/13
Also,
cos A = sin (90° - A)
therefore,
=> sin( 90°- 12/13)
=> sin 1058/13
=> sin 81.38
Hence, value of sin A = 81.38
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