Given : sec A= 29/21,evaluate : sin A - 1/tan A
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Answer:
Do not use for online exam
Here's your answer
secA=
21
29
secA=
B
H
=
21
29
Using Pythagoras Theorem,
H
2
=P
2
+B
2
29
2
=P
2
+21
2
841=441+P
2
$
P=20
Now, sinA−
tanA
1
=sinA−cotA
=
H
P
−
P
B
=
29
20
−
20
21
=
580
400−609
=
580
−209
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