Question

given sec theta =13/12 calculate all other trigonometic ratio​

Answer 1

finding cos =8

cos 8 = 1

--------

sec 8

cos 8 = 1

------

13

------

12

cos 8 = 12

------

13

side adjacent to <8

--------------––---–―-------- =12

-----

13

hypotenuse

AB. 12×

----- = --------

S AC. 13×

use pythagoras theorem to fined BC

(hypotenuse)2 =(higth)2 + ( base)2

AC2=AB2+BC2

(13×)2= (12×)2 + ( BC)2

(BC)2 = (13×)2 - (12×)2

(BC)2=(13×)2 -(12×)2

(BC)2=169×2-144×2

(BC)2=25×2

BC=

$\sqrt{25 \times 2}$

BC=

$\sqrt{52 \times 2}$

BC=5×

hope this helps you

thanks