Given sequences are A.P. ? If they are A.P. find the common difference 127, 132, 137,.
Answers
Answered by
10
Answer:
Given sequences are A.P.
Step-by-step explanation:
common difference = second term - first term
=> 132-127
=>5
Answered by
1
Step-by-step explanation:
t1=127, t2 =132 ,t3 =137
t2-t1 = 132-127=5
t3-t2 =137-132=5
t1-t2=t3-t2= 5=d=constantthe different between two consecutive terms is constant. The given sequence is anA.P common difference (d) =5
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