Given sets A={1,2,3,4}, B = {1,2}
Find number of relations of A ×B and Find R
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Answered by
2
Given,
A={1,2,3,4}
B = {1,2}
n (A) = 4
n( B) = 2
number of relations of A ×B= 2 ^ n ( A) × n( B)
=2^(4 ×2)
= 2^8.
n( A ×B) = 4 × 2=8.
R= A× B
Now, R = { (1,1) ,(1,2),(2,1),(2,2), (3,1),(3,2), (4,1), (4,2) }
A={1,2,3,4}
B = {1,2}
n (A) = 4
n( B) = 2
number of relations of A ×B= 2 ^ n ( A) × n( B)
=2^(4 ×2)
= 2^8.
n( A ×B) = 4 × 2=8.
R= A× B
Now, R = { (1,1) ,(1,2),(2,1),(2,2), (3,1),(3,2), (4,1), (4,2) }
Answered by
1
GIVEN THAT
A=[1,2,3,4]
B=[1,2]
N(A)=4
N(B)=2
NUMBER OF RELATIONS OF A×B
= 2 POWER N(A)×N(B)
= 2 POWER 4 ×2
= 2 POWER 8
N(A×B)=4×2=8
R = A×B
THEN , R = [(1,1),(1,2),(2,1),(2,2),(3,1),(3,2),(4,1),(4,2) IS THE VALUE OF R
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