Question

Given sets A and B have 12 and 8 elements respectively. What can be the minimum number of elements in AUB?​

Answer 1

Step-by-step explanation:

n(AUB) = nA + nB - n(A∩B)

Where nA=12 and nB= 8

For making minimum of (AUB) , n(A∩B) should be maximum . So AUB will reduce.

We know that (A∩B) means common term in A and B

by observation maximum common no. in A and B is 8

hence n(A∩B) = 8

Now

n(AUB) = nA + nB - n(A∩B)

= 12 + 8 - 8

= 12 Ans.....

Answer 2

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If all the elements of set A are different than set B.

The maximum no. of elements in set A U B will be 6 + 3 = 9.

If however, Set A is a subset of B, then the yotal number of elements in a set A U B will be n (B) = 6.

hope this will help you. ..

-3idiots29