Question

Given: side AC ≅ side BC, ∠A ≅ ∠B
D is the midpoint of side AB
Prove: ΔACD ≅ ΔBCD

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

ANSWER:

In ΔABC and ΔABD,

AC = AD (Given)

∠CAB = ∠DAB (AB bisects ∠A)

AB = AB (Common)

∴ ΔABC ≅ ΔABD (By SAS congruence rule)

∴ BC = BD (By CPCT)

Therefore, BC and BD are of equal lengths.