Question

Given sin A=12/37, find cos A and tan A.

Answer 1

Answer:

Step-by-step explanation:

Let a triangle...which

Angle is A, hypotenuse (h) is 37 given, perpendicular (L) is 12 and base (B).

So, sin A = 12/37

A= 18.92°

Now, cas A = B/ H

COS( 18.92) ×37 = B

BASE (B) = 35.OO

Now, cos A = 35/ 37

Cas A = 0.945

Now tan A = sinA/ Cos A

= 0.324/ 0.945

Tan A = 0.342. Or

= 12/35 ans

Answer 2

cosA = $\dfrac{35}{37}$, tanA = $\dfrac{12}{35}$

Concept to be used:

If a, b and c are the base, height and hypotenuse of a right-angled triangle, then by Pythagoras' theorem, we can get the following relation among a, b and c,

$a^{2}+b^{2}=c^{2}$

When two of a, b, c are known, we can find the other from the above relation.

Step-by-step explanation:

Given, sinA = $\dfrac{12}{37}$

Then, height = 12 and hypotenuse = 37

• Since we have to find cosA and tanA, we need the base.

So, base = $\sqrt{(hypotenuse)^{2}-(height)^{2}}$

= $\sqrt{(37)^{2}-(12)^{2}}$

= $\sqrt{1369-144}$

= $\sqrt{1225}$

= 35

Then, cosA = $\dfrac{base}{hypotenuse}$ = $\dfrac{35}{37}$

and tanA = $\dfrac{height}{base}$ = $\dfrac{12}{35}$

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