Given sin A = 2/5, and A is an acute angle ,cos A is:
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Given: sinA=2/5
>A is an acute angle .
>so, in ∆ABC we have angle B=90°
>AC=5 and BC=2.
>by phthagoras theorem
AB = √AC²- BC²
=5²-2² = 25-4 = 21
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ab nhi ho raha sorry
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