Math, asked by shreeyag8, 3 months ago

Given sin A = √3/2 cos B ,then the value of tan (A-B) is​

Answers

Answered by XxZeeshanarshiALLHA
5

Answer:

the answer for your question us 1/√3

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Answered by Anonymous
2

Given, sinA = √3/2, i.e., A = 60°

cosB = 1/2, i.e., B = 30°

Now, tan(A - B)

= tan(60° - 30°)

= tan30°

= 1/√3

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