given sin A=3/5 find a) tan A b) cos A
rutvi3:
with method please
first you use triangle and set all sides according to quation
then
sinA =perpendicular/hypot so sinA=3/5 so 3=perpendicular and 5 is hypotenious.. use pytagors and find base or base =4 ....
a can add one more same question can you solve it with the figure
then tanA =perpendicular/base so tanA =3/4
ok
Answers
Answered by
32
sinA=3/5 (because sine =p/h
hence b=root (25-9)=4
tanA=p/b and cosA =b/h
so,
tanA=3/4
cosA=4/5
hence b=root (25-9)=4
tanA=p/b and cosA =b/h
so,
tanA=3/4
cosA=4/5
figure
rutvi triangle bna lo
Ok
Answered by
15
this will help you mmmmmmmm
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