Given sin A=4/5,cosB =5/12,A andB being acute,find sin (A-B)
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according to Pythagoras theorem,
cosA=3/5,sinB=√119/12
sin(A-B)=sinAcosB-cosAsinB
=4/5×5/12-3/5×√119/12
=20/60-√119/60
hope it helps mark as brainliest
cosA=3/5,sinB=√119/12
sin(A-B)=sinAcosB-cosAsinB
=4/5×5/12-3/5×√119/12
=20/60-√119/60
hope it helps mark as brainliest
saikumar27:
no it is worng
Answered by
1
hope you find it helpful....
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in the book the answer is 33/62
sorry 33/65
can u do it
well I'll try
well, is the statement correct?
like cosB ki jgaah pe tan given ho
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